Dear Professor Cram:
Jerry was 1/3 as young as his grandfather 15 years ago. If the sum of their ages is 110, how old is Jerry's grandfather? What is the easiest way to calculate this? Thanks
Kaye B, Riverdale
Thanks for your word-problem question, Kaye. This is a system of linear equations problem, which we'll solve using the Substitution Method. (Learn more about the Systems of Linear Equations Substitution Method.) Let's review the facts first:
- Jerry's age today is J
- Grandpa's age today is G
- Jerry's age 15 years ago is (J-15)
- Grandpa's age 15 years ago is (G-15)
In equation form, then, we can express their ages 15 years ago and today like so:
- #1: J - 15 = (G-15)/3 (age 15 years ago)
- #2: J + G = 110 (age today)
Solve equation #2 for grandpa's age by subtracting J from both sides, yielding:
- #2: G = 110 - J
Now substitute this definition of G into equation #1 so we can solve for J:
- #1: J-15 = ((110-J)-15)/3, or
#1: J-15 = (95-J)/3, or
#1: 3(J-15) = (95-J), or
#1: 3J-45 = 95-J, or
#1: 3J = 95-J+45, or
#1: 3J+J = 95+45, or
#1: 4J = 140, or
#1: J = 35
So if J=35, then that means Jerry's age today is 35 years old. Using equation #2, that means Grandpa's age today is 110-35, or 75 years old.
The final step in solving this problem is one that many students forget: checking your answer! Let's put our values for J and G into equations #1 and #2 and make sure they work:
- #1: 35-15 = (75-15)/3, or
#1: 20 = (60)/3, or
#1: 20 = 20 CORRECT
- #2: 75 = 110-35, or
#2: 75 = 75 CORRECT
The correct answer, then, is that Jerry's grandfather is 75 years old.
No substitution for success,
Professor Cram
Keywords: Algebra, Linear Equations, Math, Substitution Method, Systems of Linear Equations, Systems of Linear Equations Word Problem, Word Problem


