<?xml-stylesheet type="text/xsl" href="http://www.college-cram.com/study/trigonometry/rss/rssstyles.xsl"?>
<rss version='2.0'   xmlns:dc='http://purl.org/dc/elements/1.1/'>
    <channel xml:base='http://www.college-cram.com/study/trigonometry/'>
        <title><![CDATA[Trigonometry : Activity]]></title>
        <description><![CDATA[Activity for Trigonometry, hosted on College-Cram.]]></description>
        <generator>Elgg</generator>
        <link>http://www.college-cram.com/study/trigonometry/</link>        
        <item>
            <title><![CDATA[Trigonometry Homework Help]]></title>
            <link>http://www.college-cram.com/study/trigonometry/weblog/trigonometry-homework-help</link>
            <guid isPermaLink="true">http://www.college-cram.com/study/trigonometry/weblog/trigonometry-homework-help</guid>
            <pubDate>Fri, 09 May 2008 22:30:28 GMT</pubDate>
		<dc:subject><![CDATA[angle functions]]></dc:subject>
		<dc:subject><![CDATA[bottomless worksheet]]></dc:subject>
		<dc:subject><![CDATA[bottomless worksheets]]></dc:subject>
		<dc:subject><![CDATA[complex numbers]]></dc:subject>
		<dc:subject><![CDATA[homework help]]></dc:subject>
		<dc:subject><![CDATA[trigonometric function graph]]></dc:subject>
		<dc:subject><![CDATA[trigonometry]]></dc:subject>
		<dc:subject><![CDATA[trigonometry homework help]]></dc:subject>
		<dc:subject><![CDATA[trigonometry worksheet]]></dc:subject>
		<dc:subject><![CDATA[trigonometry worksheets]]></dc:subject>
		<dc:subject><![CDATA[bottomless]]></dc:subject>
            <description><![CDATA[<p>A number of high school and college students visit our pages searching for homework help with Trigonometry. Many times they just need some extra help, and we have the resources to give Trig students the homework help they need:</p><ul><li><a href="http://www.college-cram.com/study/search/index.php?tag=angle+functions&amp;owner=22">angle functions</a></li><li><a href="http://www.college-cram.com/study/search/index.php?tag=trigonometric+function+graph&amp;owner=22">trigonometric function graph</a></li><li><a href="http://www.college-cram.com/study/search/index.php?tag=complex+numbers&amp;owner=22">complex numbers</a></li></ul><p>Try our resources and you&#39;ll find getting <a href="http://www.college-cram.com/study/help/presentations/1114"  title="better grades in less time"><strong>better grades in less time</strong></a> is easier than you might think!</p>]]></description>
        </item>
                
        <item>
            <title><![CDATA[Using the Sine Function]]></title>
            <link>http://www.college-cram.com/study/trigonometry/weblog/using-the-sine-function</link>
            <guid isPermaLink="true">http://www.college-cram.com/study/trigonometry/weblog/using-the-sine-function</guid>
            <pubDate>Thu, 09 Aug 2007 19:55:35 GMT</pubDate>
		<dc:subject><![CDATA[Function]]></dc:subject>
		<dc:subject><![CDATA[Sine]]></dc:subject>
		<dc:subject><![CDATA[Sine Function]]></dc:subject>
		<dc:subject><![CDATA[equation]]></dc:subject>
		<dc:subject><![CDATA[hypotenuse]]></dc:subject>
		<dc:subject><![CDATA[math]]></dc:subject>
		<dc:subject><![CDATA[opposite]]></dc:subject>
		<dc:subject><![CDATA[trigonometry]]></dc:subject>
		<dc:subject><![CDATA[Using the Sine Function]]></dc:subject>
            <description><![CDATA[<div id="question"> <p>Dear Professor Cram:</p> <p>An escalator is 152 feet in length rises to a platform and makes a 30 degree angle with ground. Find the height of the platform using a trigonometry equation.</p>  <p>Ekta, Middlesex Community College</p> </div>  <p>Thanks for your question, Ekta.</p>  <p>The problem you describe is a classic <span>sine</span> function equation. Imagine the platform at the top of a right triangle, with the right angle lying directly beneath it and the escalator running up the hypotenuse. The 30&deg; angle is formed between the foot of the escalator and the ground, and the height of the platform is the side opposite the angle.</p>  <p>The equation for finding the sine of an angle is:</p>  <ul>sin A = opposite/hypotenuse</ul>  <p>If you multiply both sides of this equation by the hypotenuse, you solve for the opposite side:</p>  <ul>opposite = (sin A)(hypotenuse)</ul>  <p>Now, let&#39;s substitute the values into our equation to find the answer:</p>  <ul>opposite = (sin 30&deg;)(152 feet)</ul> <ul>opposite = (0.5)(152 feet)</ul> <ul>opposite = 76 feet</ul>  <p>I hope this helps. Let us know if you need anything else.</p>  <div id="signature"><p>Good Studying,</p> <p>Professor Cram</p></div>]]></description>
        </item>
        
    </channel>
</rss>